JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
The tangent and normal to the ellipse \(3x^2 + 5y^2 = 32\) at the point \(P(2, 2)\) meet the \(x-\) axis at \(Q\) and \(R,\) respectively. Then the area(in sq. units) of the triangle \(PQR\) is
- A \(\frac {34}{15}\)
- B \(\frac {68}{15}\)
- C \(\frac {14}{3}\)
- D \(\frac {16}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac {68}{15}\)
Step-by-step Solution
Detailed explanation
\(3{x^2} + 5{y^2} = 32\) \({\left. {\frac{{dy}}{{dx}}} \right|_{\left( {2,2} \right)}} = - \frac{3}{5}\) tengent \(:y - 2 = - \frac{3}{5}\left( {x - 2} \right) \Rightarrow Q\left( {\frac{{16}}{3},0} \right)\) Normal…
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