JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let \(Q\) be the mirror image of the point \(P (1,0,1)\) with respect to the plane \(S : x + y + z =5\). If a line \(L\) passing through \((1,-1,-1)\), parallel to the line \(PQ\) meets the plane \(S\) at \(R\), then \(QR ^{2}\) is equal to
- A \(2\)
- B \(5\)
- C \(7\)
- D \(11\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
Let parallel vector of \(L=\vec{b}\) mirror image of \(Q\) on given plane \(x+y+z=5\) \(\frac{ a -1}{1}=\frac{ b -0}{1}=\frac{ c -1}{1}=\frac{-2(2-5)}{3}\) \(a =3, b =2, c =3\) \(Q \equiv(3,2,3)\) \(\because \overrightarrow{ b }|| \overrightarrow{ PQ }\)…
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