JEE Mains · Maths · STD 11 - 8. sequence and series
Consider an arithmetic series and a geometric series having four initial terms from the set \(\{11,8,21,16,26,32,4\}\) If the last terms of these series are the maximum possible four digit numbers, then the number of common terms in these two series is equal to .......
- A \(3\)
- B \(1\)
- C \(2\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
\(G P : 4,8,16,32,64,128,256,512,1024,2048,4096,8192\) \(A P : 11,16,21,26,31,36\) Common terms : \(16,256,4096\) only
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