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JEE Mains · Maths · STD 11 - 8. sequence and series

The sum of the series : \((2)^2 + 2(4)^2 + 3(6)^2 + ...\) upto \(10\) terms is

  1. A \(11300\)
  2. B \(11200\)
  3. C \(12100\)
  4. D \(12300\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(12100\)

Step-by-step Solution

Detailed explanation

\({2^2} + 2{\left( 4 \right)^2} + 3{\left( 6 \right)^2} + .......upto\,\,10\,terms\) \( = {2^2}\left[ {{1^3} + {2^3} + {3^3} + ........upto\,\,10\,terms} \right]\) \( = 4.{\left( {\frac{{10 \times 11}}{2}} \right)^2} = 12100\)
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