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JEE Mains · Maths · STD 12 - 1. relation and function

Let \(P\) be the relation defined on the set of all real numbers such that  \(P = \left\{ {\left( {a,b} \right):{{\sec }^2}\,a - {{\tan }^2}\,b = 1\,} \right\}\). Then \(P\) is

  1. A reflexive and symmetric but not transitive
  2. B reflexive and transitive but not symmetric
  3. C symmetric and transitive but not reflexive
  4. D an equivalence relation
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Answer & Solution

Correct Answer

(D) an equivalence relation

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Detailed explanation

\(P = \left\{ {\left( {a,b} \right):{{\sec }^2}a - {{\tan }^2}b = 1} \right\}\) For reflexive: \({\sec ^2}a - {\tan ^2}b = 1\) \(\left( {true\,\,\forall \,\,a} \right)\) For symmetric: \({\sec ^2}b - {\tan ^2}a = 1\) \(L.H.S\)…
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