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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

Let \(\mathrm{P}\) be a parabola with vertex \((2,3)\) and directrix \(2 x+y=6\). Let an ellipse \(E: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a>b\) of eccentricity \(\frac{1}{\sqrt{2}}\) pass through the focus of the parabola \(\mathrm{P}\). Then the square of the length of the latus rectum of \(\mathrm{E}\), is

  1. A \(\frac{385}{8}\)
  2. B \(\frac{347}{8}\)
  3. C \(\frac{512}{25}\)
  4. D \(\frac{656}{25}\)
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Correct Answer

(D) \(\frac{656}{25}\)

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Detailed explanation

\(\text {Slope of axis }=\frac{1}{2}\) \(y-3=\frac{1}{2}(x-2)\) \(\Rightarrow 2 y-6=x-2\) \(\Rightarrow 2 y-x-4=0\) \(2 x+y-6=0\) \(4 x+2 y-12=0\) \(\alpha+1.6=4 \Rightarrow \alpha=2.4\) \(\beta+2.8=6 \Rightarrow \beta=3.2\) Ellipse passes through \((2.4,3.2)\)…
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