ExamBro
ExamBro
JEE Mains · Maths · STD 11 - Trigonometrical equations

A man is observing, from the top of a tower, a boat speeding towards the tower from a certain point A, with uniform speed. At that point, angle of depression of the boat with the man's eye is \(30^{\circ}\) (Ignore man's height). After sailing for \(20\) seconds, towards the base of the tower (which is at the level of water), the boat has reached a point \(B\), where the angle of depression is \(45^{\circ}\). Then the time taken (in seconds) by the boat from \(B\) to reach the base of the tower is

  1. A \(10\)
  2. B \(10 \sqrt{3}\)
  3. C \(10(\sqrt{3}+1)\)
  4. D \(10(\sqrt{3}-1)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(10(\sqrt{3}+1)\)

Step-by-step Solution

Detailed explanation

Let speed of boat is \(u m / s\) and height of tower is \(h\) meter \(\&\) distance \(AB = x\) metre \(\therefore x=h \cot 30^{\circ}-h \cot 45^{\circ}\) \(\Rightarrow x=h(\sqrt{3}-1)\) \(\therefore u =\frac{ x }{20}=\frac{ h (\sqrt{3}-1)}{20} m / s\) \(\therefore\) Time taken…
Same subject
Explore more questions on app