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JEE Mains · Maths · STD 12 - 1. relation and function

Let \(N\) be the set of natural numbers and two functions \(f\) and \(g\) be defined as \(f\), \(g : N \to N\) such that \(f\left( n \right) = \left\{ \begin{gathered}
  \frac{{n + 1}}{2}\,\,\,\,\,\,\,\,\,\,\,{\text{if n is odd}} \hfill \\
  \frac{n}{2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{if n is even}} \hfill \\ 
\end{gathered}  \right.\) and \(g(n) = n - (-1)^n\). Then \(fog\) is

  1. A onto but not one-one.
  2. B one-one but not onto.
  3. C both one-one and onto.
  4. D neither one-one nor onto.
Verified Solution

Answer & Solution

Correct Answer

(A) onto but not one-one.

Step-by-step Solution

Detailed explanation

\(\left. \begin{array}{l} f\left( {g\left( 1 \right)} \right) = 1\\ f\left( {g\left( 2 \right)} \right) = 1 \end{array} \right\}\) Many one \(f\left( {g\left( {2k} \right)} \right) = k\) \(f\left( {g\left( {2k + 1} \right)} \right) = k + 1\) \(\therefore \) Onto
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