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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

If the system of linear equations \(2 x-3 y=\gamma+5\) ; \(\alpha x+5 y=\beta+1\), where \(\alpha, \beta, \gamma \in R\) has infinitely many solutions, then the value of \(|9 \alpha+3 \beta+5 \gamma|\) is equal to

  1. A \(56\)
  2. B \(89\)
  3. C \(58\)
  4. D \(30\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(58\)

Step-by-step Solution

Detailed explanation

\(2 x-3 y=\gamma+5\) \(\alpha x+5 y=\beta+1\) Infinite many solution \(\frac{\alpha}{2}=\frac{5}{-3}=\frac{\beta+1}{\gamma+5}\) \(\alpha=\frac{-10}{3}, \quad 5 \gamma+25=-3 \beta-3\) \(9 \alpha=-30, \quad 3 \beta+5 \gamma=-28\) \(\text { Now, } 9 \alpha+3 \beta+5 \gamma=-58\)…