JEE Mains · Maths · STD 12 - 1. relation and function

Let \(f : R \to R\) be defined by \(f\left( x \right) = \frac{{\left| x \right| - 1}}{{\left| x \right| + 1}}\) then \(f\) is

A both one-one and onto
B one-one but not onto
C onto but not one-one
D neither one-one nor onto.

Verified Solution

Answer & Solution

Correct Answer

(C) onto but not one-one

Step-by-step Solution

Detailed explanation

\(f\left( x \right) = \frac{{\left| x \right| - 1}}{{\left| x \right| + 1}}\) for one -one function if \(f\left( {{x_1}} \right) = f\left( {{x_2}} \right)\) then \({{x_1}}\) must be equal \({{x_2}}\) Let \(f\left( {{x_1}} \right) = f\left( {{x_2}} \right)\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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