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JEE Mains · Maths · STD 11 - 12. limits

Let \(\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R}\) be a function such that \(\mathrm{f}(2)=4\) and \(\mathrm{f}^{\prime}(2)=1\). Then, the value of \(\lim _{x \rightarrow 2} \frac{x^{2} f(2)-4 f(x)}{x-2}\) is equal to:

  1. A \(4\)
  2. B \(8\)
  3. C \(16\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(12\)

Step-by-step Solution

Detailed explanation

Apply L'Hopital Rule \(\lim _{x \rightarrow 2}\left(\frac{2 x f(2)-4 f^{\prime}(x)}{1}\right)\) \(=\frac{4(4)-4}{1}=12\)
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