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JEE Mains · Maths · STD 11 - 12. limits
Let \(\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R}\) be a function such that \(\mathrm{f}(2)=4\) and \(\mathrm{f}^{\prime}(2)=1\). Then, the value of \(\lim _{x \rightarrow 2} \frac{x^{2} f(2)-4 f(x)}{x-2}\) is equal to:
- A \(4\)
- B \(8\)
- C \(16\)
- D \(12\)
Answer & Solution
Correct Answer
(D) \(12\)
Step-by-step Solution
Detailed explanation
Apply L'Hopital Rule \(\lim _{x \rightarrow 2}\left(\frac{2 x f(2)-4 f^{\prime}(x)}{1}\right)\) \(=\frac{4(4)-4}{1}=12\)
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