JEE Mains · Maths · STD 11 - 3. trignometrical ratios,functions and identities
Let \(f\) be an odd function defined on the set of real numbers such that for \(x \geq 0\) , \(f(x)\, =3\, sin\, x + 4\, cos\, x\). Then \(f(x)\) at \(x = - \frac{{11\pi }}{6}\) is equal to
- A \(\frac{3}{2} + 2\sqrt 3 \)
- B \(-\frac{3}{2} + 2\sqrt 3 \)
- C \(\frac{3}{2} - 2\sqrt 3 \)
- D \(-\frac{3}{2} - 2\sqrt 3 \)
Answer & Solution
Correct Answer
(C) \(\frac{3}{2} - 2\sqrt 3 \)
Step-by-step Solution
Detailed explanation
Given \(f\) be an odd function \(f(x)\, = \,3\,\sin x + 4\,\cos x\) Now, \(f\left( {\frac{{ - 11\pi }}{6}} \right)\, = \,3\,\sin \left( {\frac{{ - 11\pi }}{6}} \right)\, + 4\,\cos \left( {\frac{{ - 11\pi }}{6}} \right)\,\)…
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