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JEE Mains · Maths · STD 11- 2. Relation and Function

Let \(f\) be a function such that \(f(x)+3 f\left(\frac{24}{x}\right)\) \(=4 x, x \neq 0\). Then \(f(3)+f(8)\) is equal to

  1. A \(11\)
  2. B \(10\)
  3. C \(12\)
  4. D \(13\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(11\)

Step-by-step Solution

Detailed explanation

\(f(x)+3 f\left(\frac{24}{x}\right)=4 x\) Put \(x=3 \quad f(3)+3 f(8)=12\) Put \(x=8 \quad f(8)+3 f(3)=32\) Add both \(\quad 4(\mathrm{f}(3)+\mathrm{f}(8))=44\) \(f(3)+f(8)=11\)
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