JEE Mains · Maths · STD 11- 2. Relation and Function
Let \(f\) be a function such that \(f(x)+3 f\left(\frac{24}{x}\right)\) \(=4 x, x \neq 0\). Then \(f(3)+f(8)\) is equal to
- A \(11\)
- B \(10\)
- C \(12\)
- D \(13\)
Answer & Solution
Correct Answer
(A) \(11\)
Step-by-step Solution
Detailed explanation
\(f(x)+3 f\left(\frac{24}{x}\right)=4 x\) Put \(x=3 \quad f(3)+3 f(8)=12\) Put \(x=8 \quad f(8)+3 f(3)=32\) Add both \(\quad 4(\mathrm{f}(3)+\mathrm{f}(8))=44\) \(f(3)+f(8)=11\)
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