JEE Mains · Maths · STD 12 - 7.2 definite integral
\(\int \limits_{\frac{3 \sqrt{2}}{4}}^{\frac{3 \sqrt{3}}{4}} \frac{48}{\sqrt{9-4 x^2}} d x\) is equal to
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{6}\)
- D \(2 \pi\)
Answer & Solution
Correct Answer
(D) \(2 \pi\)
Step-by-step Solution
Detailed explanation
\(\int \limits_{\frac{3 \sqrt{2}}{4}}^{\frac{3 \sqrt{3}}{4}} \frac{48}{\sqrt{9-4 x^2}} d x\) We have \(\int \frac{d x}{\sqrt{a^2-x^2}}=\sin ^{-1} \frac{x}{a}+C\)…
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