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JEE Mains · Maths · STD 11 - 8. sequence and series

Let \(a_1 , a_2, a_3, .... , a_n\), be in \(A.P\). If \(a_3 + a_7 + a_{11} + a_{15} = 72\) , then the sum of its first \(17\) terms is equal to

  1. A \(306\)
  2. B \(204\)
  3. C \(153\)
  4. D \(612\)
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Answer & Solution

Correct Answer

(A) \(306\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{l} {a_3} + {a_7} + {a_{11}} + {a_{15}} = 72\\ \left( {{a_3} + {a_{15}}} \right) + \left( {{a_7} + {a_{11}}} \right) = 72\\ {a_3} + {a_{15}} + {a_7} + {a_{11}} = \left( {{a_1} + {a_{17}}} \right) \end{array}\)…
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