JEE Mains · Maths · STD 12 - 5. continuity and differentiation
Let \(f:(-2,2) \rightarrow\) IR be defined by \(f(x)=\left\{\begin{array}{cc}x[x] & ,-2 < x < 0 \\(x-1)[x] & , 0 \leq x < 2\end{array}\right.\) Where \([x]\) denotes the greatest integer function. If \(m\) and \(n\) respectively are the number of points in \((-2,2)\) at which \(y =|f(x)|\) is not continuous and not differentiable, then \(m + n\) is equal to \(...........\).
- A \(3\)
- B \(2\)
- C \(1\)
- D \(4\)
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
\(f(x)=\left\{\begin{array}{cl}x[x] & ,-2 < x < 0 \\ (x-1)[x] & , 0 \leq x < 2\end{array}\right.\) \(|f(x)|=\text { Remain same }\) \(m =1, n =3\) \(m + n =4\)
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