JEE Mains · Maths · STD 12 - 5. continuity and differentiation
Let \([\bullet]\) denote the greatest integer function, and let \(f(x)=\min \left\{\sqrt{2} x, x^2\right\}\). Let \(S=\{x \in(-2,2):\) the function \(g ( x )=| x |\left[ x ^2\right]\) is discontinuous at x \(\}\). Then \(\sum_{x \in S} f(x)\) equals :
- A \(2-\sqrt{2}\)
- B \(2 \sqrt{6}-3 \sqrt{2}\)
- C \(1-\sqrt{2}\)
- D \(\sqrt{6}-2 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(1-\sqrt{2}\)
Step-by-step Solution
Detailed explanation
\(g ( x )=| x |\left[ x ^2\right]\) points of discontinuity of \(g(x)\) in \((-2,2)\) are \(( \pm 1, \pm \sqrt{2}, \pm \sqrt{3})\) \(\therefore S =\{-1,1,-\sqrt{2}, \sqrt{2},-\sqrt{3}, \sqrt{3}\}\) \(\because f(x)=\min \left\{\sqrt{2} x, x^2\right\}\)…
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