JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\vec{a} = 2\hat{i} + 3\hat{j} + 3\hat{k}\) and \(\vec{b} = 6\hat{i} + 3\hat{j} + 3\hat{k}\). Then the square of the area of the triangle with adjacent sides determined by the vectors \((2\vec{a} + 3\vec{b})\) and \((\vec{a} - \vec{b})\) is :
- A \(450\)
- B \(900\)
- C \(1800\)
- D \(2400\)
Answer & Solution
Correct Answer
(C) \(1800\)
Step-by-step Solution
Detailed explanation
The area of a triangle with adjacent sides \(\vec{u}\) and \(\vec{v}\) is given by \(\Delta = \dfrac{1}{2} |\vec{u} \times \vec{v}|\). Here, \(\vec{u} = 2\vec{a} + 3\vec{b}\) and \(\vec{v} = \vec{a} - \vec{b}\).…
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