JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the shortest distance between the line joining the points \((1, 2, 3)\) and \((2,3,4)\), and the line \(\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z-2}{0}\) is \(\alpha\), then \(28 \alpha^2\) is equal to \(........\).
- A \(18\)
- B \(17\)
- C \(16\)
- D \(15\)
Answer & Solution
Correct Answer
(A) \(18\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ r }=(\hat{ i }+2 \hat{ j }+3 \hat{ k })+\lambda(\hat{ i }+\hat{ j }+\hat{ k }) \overrightarrow{ r }=\overrightarrow{ a }+\lambda \overrightarrow{ p }\)…
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