JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
A hyperbola has its centre at the origin, passes through the point \((4, 2)\) and has transverse axis of length \(4\) along the \(x -\) axis. Then the eccentricity of the hyperbola is
- A \(\frac {2}{\sqrt 3}\)
- B \(\frac {3}{2}\)
- C \(\sqrt 3\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(\frac {2}{\sqrt 3}\)
Step-by-step Solution
Detailed explanation
Given hyperbolo is \(\frac{{{x^2}}}{4} - \frac{{{y^2}}}{{{b^2}}} = 1\) Satisfying the point \(\left( {4,2} \right)\) \( \Rightarrow {b^2} = \frac{4}{3}\) \( \Rightarrow e = \frac{2}{{\sqrt 3 }}\)
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