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JEE Mains · Maths · STD 11 - 12. limits

If \(\lim \limits_{x \rightarrow 1} \frac{x+x^{2}+x^{3}+\ldots+x^{n}-n}{x-1}=820,(n \in N)\) then the value of \(n\) is equal to

  1. A \(35\)
  2. B \(45\)
  3. C \(40\)
  4. D \(50\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(40\)

Step-by-step Solution

Detailed explanation

\(\lim _{x \rightarrow 1} \frac{x+x^{2}+\ldots \ldots+x^{2}-n}{x-1}=820\) \(\Rightarrow \quad \lim _{x \rightarrow 1}\left(\frac{x-1}{x-1}+\frac{x^{2}-1}{x-1}+\ldots . . \frac{x^{n}-1}{x-1}\right)=820\) \(\Rightarrow 1+2+\ldots .+n=820\) \(\Rightarrow \quad n(n+1)=2 \times 820\)…