JEE Mains · Maths · STD 11 - 7. binomial theoram
\(50^{\text {th }}\) root of a number \(x\) is \(12\) and \(50^{\text {th }}\) root of another number \(y\) is \(18\) . Then the remainder obtained on dividing \(( x + y )\) by \(25\) is \(........\).
- A \(21\)
- B \(23\)
- C \(22\)
- D \(20\)
Answer & Solution
Correct Answer
(B) \(23\)
Step-by-step Solution
Detailed explanation
\(x + y =12^{50}+18^{50}=(150-6)^{25}+(325-1)^{25}\) \(=25 K -\left(6^{25}+1\right)=25 K -\left((5+1)^{25}+1\right)\) \(=25 K _1-2 \quad \text { Remainder }=23\)
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