JEE Mains · Maths · STD 12 - 11. three dimension geometry
The plane containing the line \(\frac{{x - 1}}{1} = \frac{{y - 2}}{2} = \frac{{z - 3}}{3}\) and parallel to the line \(\frac{x}{1} = \frac{y}{1} = \frac{z}{4}\) passes through the point
- A \((1, - 2, 5)\)
- B \((1, 0, 5)\)
- C \((0, 3, -5)\)
- D \(( -1,- 3, 0)\)
Answer & Solution
Correct Answer
(B) \((1, 0, 5)\)
Step-by-step Solution
Detailed explanation
Equation of the plane containing the line \(\frac{x-1}{1}=\frac{y-2}{2}=\frac{z-3}{3}\) is \(a(x-1)+b(v-2)+c(z-3)=0\) .....\((i)\) where \(a \cdot 1+b \cdot 2+c \cdot 3=0\) i.e., \(\quad a+2 b+3 c=0\) ....\((ii)\) Since the plane \((i)\) parallel to the line…
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