JEE Mains · Maths · STD 12 - 7.2 definite integral
Let \(f\) be a twice differentiable function such that \(f(x)=\int_{0}^{x}\tan(t-x)dt-\int_{0}^{x}f(t)\tan t\,dt\), \(x \in \left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right)\). Then \(f''\left(\dfrac{\pi}{6}\right)+12f'\left(-\dfrac{\pi}{6}\right)+f\left(\dfrac{\pi}{6}\right)\) is equal to ______
- A 4
- B 5
- C 6
- D 9
Answer & Solution
Correct Answer
(B) 5
Step-by-step Solution
Detailed explanation
Given the function: \(f(x) = \int_{0}^{x} \tan(t-x) dt - \int_{0}^{x} f(t) \tan t \, dt\) First, we simplify the first integral. Let \(u = x - t\), then \(du = -dt\). When \(t = 0\), \(u = x\); when \(t = x\), \(u = 0\).…
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