JEE Mains · Maths · STD 11 - 9. straight line
If the image of the point \((-4,5)\) in the line \(x+2 y=2\) lies on the circle \((x+4)^2+(y-3)^2=r^2\), then \(r\) is equal lo:
- A \(1\)
- B \(2\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
Image of point \((-4,5)\) \(\frac{\mathrm{x}-\mathrm{x}_1}{\mathrm{a}}=\frac{\mathrm{y}-\mathrm{y}_1}{\mathrm{~b}}=-2\left(\frac{\mathrm{ax_{1 } + \mathrm { by } _ { 1 } + \mathrm { c }}}{\mathrm{a}^2+\mathrm{b}^2}\right)\) Line : \(x+2 y-2=0\)…
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