JEE Mains · Maths · STD 11 - 9. straight line
Two sides of a parallelogram are along the lines \(4 x+5 y=0\) and \(7 x+2 y=0\). If the equation of one of the diagonals of the parallelogram is \(11 \mathrm{x}+7 \mathrm{y}=9\), then other diagonal passes through the point:
- A \((1,3)\)
- B \((1,2)\)
- C \((2,2)\)
- D \((2,1)\)
Answer & Solution
Correct Answer
(C) \((2,2)\)
Step-by-step Solution
Detailed explanation
Both the lines pass through origin. point \(D\) is equal of intersection of \(4 x+5 y=0\, \,11 x+7 y=9\) So, coordinates of point \(D=\left(\frac{5}{3},-\frac{4}{3}\right)\) Also, point \(B\) is point of intersection of \(7 x+2 y=0\, \, 11 x+7 y=9\) So, coordinates of point…
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