JEE Mains · Maths · STD 11 - 9. straight line
If for \(\theta \in\left[-\frac{\pi}{3}, 0\right]\), the points \((x, y)=\left(3 \tan \left(\theta+\frac{\pi}{3}\right), 2 \tan \left(\theta+\frac{\pi}{6}\right)\right)\) lie on \(x y+\alpha x+\beta y+\gamma=0\), then \(\alpha^2+\beta^2+\gamma^2\) is equal to :
- A 80
- B 72
- C 96
- D 75
Answer & Solution
Correct Answer
(D) 75
Step-by-step Solution
Detailed explanation
\begin{aligned} & x=3\left(\frac{\tan \theta+\sqrt{3}}{1-\sqrt{3} \tan \theta}\right) \\ & x-\sqrt{3} \tan \theta=3 \tan \theta+3 \sqrt{3} \\ & \tan \theta=\frac{x-3 \sqrt{3}}{3+\sqrt{3} x} \ldots(1) \\ & 2\left(\frac{\tan \theta+\frac{1}{\sqrt{3}}}{1-\frac{\tan…
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