JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
If \(f(\theta ) =\left| {\begin{array}{*{20}{c}}
1&{\cos {\mkern 1mu} \theta }&1\\
{ - \sin {\mkern 1mu} \theta }&1&{ - \cos {\mkern 1mu} \theta }\\
{ - 1}&{\sin {\mkern 1mu} \theta }&1
\end{array}} \right|\) and \(A\) and \(B\) are respectively the maximum and the minimum values of \(f(\theta )\), then \((A , B)\) is equal to
- A \((3, - 1)\)
- B \(( 4,2-\sqrt 2 )\)
- C \((2 + \sqrt 2 ,2 - \sqrt 2 )\)
- D \((2 + \sqrt 2 , - 1)\)
Answer & Solution
Correct Answer
(C) \((2 + \sqrt 2 ,2 - \sqrt 2 )\)
Step-by-step Solution
Detailed explanation
Let \(f\left( \theta \right) = \begin{array}{*{20}{c}} 1&{\cos \theta }&1\\ { - \sin \theta }&1&{ - \cos \theta }\\ { - 1}&{\sin \theta }&1 \end{array}\)…
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