JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
If the \(x\)-intercept of a focal chord of the parabola \(y^2=8 x+4 y+4\) is \(3\) , then the length of this chord is equal to \(.............\)
- A \(15\)
- B \(16\)
- C \(14\)
- D \(13\)
Answer & Solution
Correct Answer
(B) \(16\)
Step-by-step Solution
Detailed explanation
\(y^2=8 x+4 y+4\) \((y-2)^2=8(x+1)\) \(y^2=4 a x\) \(a=2, X=x+1, Y=y-2\) focus \((1,2)\) \(y -2= m ( x -1)\) Put \((3,0)\) in the above line \(m =-1\) Length of focal chord \(=16\)
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