JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
If a hyperbola passes through the point \(\mathrm{P}(10,16)\) and it has vertices at \((\pm 6,0),\) then the equation of the normal to it at \(P\) is
- A \(x+2 y=42\)
- B \(3 x+4 y=94\)
- C \(2 x+5 y=100\)
- D \(x+3 y=58\)
Answer & Solution
Correct Answer
(C) \(2 x+5 y=100\)
Step-by-step Solution
Detailed explanation
\(\frac{x^{2}}{36}-\frac{y^{2}}{b^{2}}=1\) \(\mathrm{P}(10,16)\) lies on ( i ) get \(\mathrm{b}^{2}=144\) \(\frac{x^{2}}{36}-\frac{y^{2}}{144}=1\) Equation of normal is…
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