JEE Mains · Maths · STD 11 - 3. trignometrical ratios,functions and identities
If \(\frac{\sqrt{2} \sin \alpha}{\sqrt{1+\cos 2 \alpha}}=\frac{1}{7}\) and \(\sqrt{\frac{1-\cos 2 \beta}{2}}=\frac{1}{\sqrt{10}}\) \(\alpha, \beta \in\left(0, \frac{\pi}{2}\right),\) then \(\tan (\alpha+2 \beta)\) is equal to
- A \(1\)
- B \(2\)
- C \(2.5\)
- D \(3.5\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(\frac{\sqrt{2} \sin \alpha}{\sqrt{2} \cos \alpha}=\frac{1}{7} \Rightarrow \tan \alpha=\frac{1}{7}\) \(\sin \beta=\frac{1}{\sqrt{10}} \Rightarrow \tan \beta=\frac{1}{3} \Rightarrow \tan 2 \beta=\frac{3}{4}\)…
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