JEE Mains · Maths · STD 12 - 1. relation and function
Let \(S=\{1,2,3,4,5,6,7,8,9,10\}\). Define \(f: S \rightarrow S\) as \(f(n)=\left\{\begin{array}{cc}2 n, & \text { if } n=1,2,3,4,5 \\ 2 n-11 & \text { if } n=6,7,8,9,10\end{array}\right.\). Let \(g : S \rightarrow S\) be a function such that \(f o g(n)=\left\{\begin{array}{ll}n+1 & \text {, if } n \text { is odd } \\ n-1 & \text {, if } n \text { is even }\end{array}\right.\), then \(g (10)(( g (1)+ g (2)+ g (3)+ g (4)+ g (5))\) is equal to
- A \(-190\)
- B \(180\)
- C \(-180\)
- D \(190\)
Answer & Solution
Correct Answer
(D) \(190\)
Step-by-step Solution
Detailed explanation
\(\quad f ^{-1}( n )=\left\{\begin{array}{cc}\frac{ n }{2} ; & n =2,4,6,8,10 \\ \frac{ n +11}{2} ; & n =1,3,5,7,9\end{array}\right.\) \(\therefore \quad f ( g ( n ))=\left\{\begin{array}{lll} n +1 ;& n \in \text { odd } \\ n -1 ; &n \in \text { even } \end{array}\right.\)…
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