JEE Mains · Maths · STD 11 - 12. limits
\(\lim _{t \rightarrow 0}\left(1^{\frac{1}{\sin ^2 t}}+2^{\frac{1}{\sin ^2 t}}+\ldots .+n^{\frac{1}{\sin ^2 t}}\right)^{\sin ^2 t}\) is equal to \(.......\)
- A \(n^2+n\)
- B \(n\)
- C \(\frac{ n ( n +1)}{2}\)
- D \(n^2\)
Answer & Solution
Correct Answer
(B) \(n\)
Step-by-step Solution
Detailed explanation
\begin{array}{l}\lim _{t \rightarrow 0}\left(1^{\operatorname{cosec}^2 t}+2^{\operatorname{cosec}^2 t}+\ldots \ldots . .+n^{\operatorname{cosec}^2 t}\right)^{\sin ^2 t} \\ =\lim _{t \rightarrow 0} n \left(\left(\frac{1}{n}\right)^{\operatorname{cosec}^2…
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