JEE Mains · Maths · STD 12 - 11. three dimension geometry
Consider the line \(L\) given by the equation \(\frac{x-3}{2}=\frac{y-1}{1}=\frac{z-2}{1}\). Let \(Q\) be the mirror image of the point \((2,3,-1)\) with respect to \(L\). Let a plane \(P\) be such that it passes through \(Q\), and the line \(L\) is perpendicular to \(P.\) Then which of the following points is on the plane \(P\) ?
- A \((1,2,2)\)
- B \((-1,1,2)\)
- C \((1,1,1)\)
- D \((1,1,2)\)
Answer & Solution
Correct Answer
(A) \((1,2,2)\)
Step-by-step Solution
Detailed explanation
Plane \(p\) is \(\perp\) to line \(\frac{x-3}{2}=\frac{y-1}{1}=\frac{z-2}{1}\) \(\&\) passes through pt. \((2,3,-1)\) equation of plane \(p\) \(2(x-2)+1(y-3)+1(z+1)=0\) \(2 x+y+z-6=0\) \(\mathrm{pt}(1,2,2)\) satisfies above equation
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