JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
A chord is drawn through the focus of the parabola \(y^2\, = 6x\) such that its distance from the vertex of this parabola is \(\frac{{\sqrt 5 }}{2}\) , then its slope can be:
- A \(\frac{{\sqrt 5 }}{2}\)
- B \(\frac{{\sqrt 3 }}{2}\)
- C \(\frac{2}{{\sqrt 5 }}\)
- D \(\frac{2}{{\sqrt 3 }}\)
Answer & Solution
Correct Answer
(A) \(\frac{{\sqrt 5 }}{2}\)
Step-by-step Solution
Detailed explanation
Equation of parabola, \({y^2} = 6x\) \( \Rightarrow {y^2} = 4 \times \frac{3}{2}x\) \(\therefore \) Focus \( = \left( {\frac{3}{2},0} \right)\) Let equation of chord passing throught focus be \(ax + by + c = 0\,\,\,\,\,\,\,.......\left( 1 \right)\) Since chord is passinh…
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