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JEE Mains · Maths · STD 11 - 13. statistics

Consider the following frequency distribution:
Class: \(10-20\) \(20-30\) \(30-40\) \(40-50\) \(50-60\)
Freq: \(\alpha\) \(110\) \(54\) \(30\) \(\beta\)
If the sum of all frequencies is \(584\) and median is \(45\) , then \(|\alpha-\beta|\) is equal to \(.....\)

  1. A \(390\)
  2. B \(164\)
  3. C \(377\)
  4. D \(113\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(164\)

Step-by-step Solution

Detailed explanation

\(Class\) \(Frequency\) \(C.F.\) \(10-20\) \(\alpha\) \(\alpha\) \(20-30\) \(110\) \(\alpha+110\) \(30-40\) \(54\) \(\alpha+164\) \(40-50\) \(30\) \(\alpha+194\) \(50-60\) \(\beta\) \(\alpha+\mathrm{b}+194=584\) \(\mathrm{N}=\sum \mathrm{f}=584\) \(\alpha+\beta=390\) Median…