JEE Mains · Maths · STD 11 - 6. permutation and combination
Consider a class of \(5\) girls and \(7\) boys. The number of different teams consisting of \(2\) girls and \(3\) boys that can be formed from this class, if there are two specific boys \(A\) and \(B\), who refuse to be the members of the same team, is
- A \(500\)
- B \(200\)
- C \(300\)
- D \(350\)
Answer & Solution
Correct Answer
(C) \(300\)
Step-by-step Solution
Detailed explanation
Number of ways \(=\) Total number of ways without restriction \(-\) When two specific boys are in team without any restriction, total number of ways of forming team is \(^7{C_3}{ \times ^5}{C_2} = 350\) If two specific boys \(B_1,B_2\) are in same team then total number of ways…
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