JEE Mains · Maths · STD 12 - 13. probability
An urn contains \(5\) red and \(2\) green balls. A ball is drawn at random from the urn. If the drawn ball is green, then a red ball is added to the urn and if the drawn ball is red, then a green ball is added to the urn; the original ball is not returned to the urn. Now, a second ball is drawn at random from it. The probability that the second ball is red, is
- A \(\frac {26}{49}\)
- B \(\frac {32}{49}\)
- C \(\frac {27}{49}\)
- D \(\frac {21}{49}\)
Answer & Solution
Correct Answer
(B) \(\frac {32}{49}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{E}_{1}:\) Event of drawing a Red ball and placing a green ball in the bag \(\mathrm{E}_{2}:\) Event of drawing a green ball and placing a red ball in the bag \(E:\) Event of drawing a red ball in second draw…
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