JEE Mains · Maths · STD 11 - 9. straight line
A straight line through origin \(O\) meets the lines \(3y= 10 - 4x\) and \(8x + 6y+ 5 = 0\) at points\( A\) and \(B\) respectively. Then \(O\) divides the segment \(AB\) in the ratio
- A \(2:3\)
- B \(1:2\)
- C \(4:1\)
- D \(3:4\)
Answer & Solution
Correct Answer
(C) \(4:1\)
Step-by-step Solution
Detailed explanation
Length of \( \bot \) to \(4x+3y=10\) from origin \((0,0)\) \({P_1} = \frac{{10}}{5} = 2\) Length of \( \bot \) to \(8x+6y+5=0\) from origin \((0,0)\) \({P_2} = \frac{5}{{10}} = \frac{1}{2}\) Lines are parallel to each other \( \Rightarrow \) ratio will be \(4:1\) or \(1:4\)
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