JEE Mains · Maths · STD 11 - 9. straight line
A straight line \(L\) through the point \((3, - 2)\) is inclined at an angle of \(60^o\) to the line \(\sqrt 3 x + y = 1\) . If \(L\) also intersects the \(x-\) axis, then the equation of \(L\) is
- A \(y + \sqrt 3 x + 2 - 3\sqrt 3 = 0\)
- B \(\sqrt 3 y + x - 3 + 2\sqrt 3 = 0\)
- C \(y - \sqrt 3 x + 2 + 3\sqrt 3 = 0\)
- D \(\sqrt 3 y - x + 3 + 2\sqrt 3 = 0\)
Answer & Solution
Correct Answer
(C) \(y - \sqrt 3 x + 2 + 3\sqrt 3 = 0\)
Step-by-step Solution
Detailed explanation
Given eqn of line is \(y + \sqrt 3 x - 1 = 0\) \( \Rightarrow y = - \sqrt 3 x + 1\) \( \Rightarrow \) (slope) \({m_2} = - \sqrt 3 \) Let the other slope be \({m_1}\)…
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