JEE Mains · Maths · STD 12 - 13. probability
Out of \(11\) consecutive natural numbers if three numbers are selected at random (without repetition), then the probability that they are in \(A.P.\) with positive common difference, is
- A \(\frac{15}{101}\)
- B \(\frac{5}{101}\)
- C \(\frac{5}{33}\)
- D \(\frac{10}{99}\)
Answer & Solution
Correct Answer
(C) \(\frac{5}{33}\)
Step-by-step Solution
Detailed explanation
Out of 11 consecutive natural numbers either 6 even and 5 odd numbers or 5 even and 6 odd numbers when 3 numbers are selected at random then total cases \(={ }^{11} C _{3}\) since these 3 numbers are in A.P. Let no's are \(a, b, c\) \(2 b \Rightarrow\) even number…
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