JEE Mains · Maths · STD 11 - 9. straight line
A ray of light is incident along a line which meets another line, \(7x- y+ 1 =0\), at the point \((0, 1)\) . The ray is then reflected from this point along the line, \(y + 2x = 1\) . Then the equation of the line of incidence of the ray of light is
- A \(41x - 25y+25=0\)
- B \(41x + 25y- 25=0\)
- C \(41x - 38y+ 38=0\)
- D \(41x+38y- 38=0\)
Answer & Solution
Correct Answer
(C) \(41x - 38y+ 38=0\)
Step-by-step Solution
Detailed explanation
Let slope of incident ray be \(m\) \(\therefore \) angle of incidence =angle of reflection \(\therefore \left| {\frac{{m - 7}}{{1 + 7m}}} \right| = \left| {\frac{{ - 2 - 7}}{{1 - 14}}} \right| = \frac{9}{{13}}\) \( \Rightarrow \frac{{m - 7}}{{1 + 7m}} = \frac{9}{{13}}\,\,\,\,\)…
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