JEE Mains · Maths · STD 12 - 13. probability
A fair die is thrown until \(2\) appears. Then the probability, that \(2\) appears in even number of throws, is
- A \(\frac{5}{6}\)
- B \(\frac{1}{6}\)
- C \(\frac{5}{11}\)
- D \(\frac{6}{11}\)
Answer & Solution
Correct Answer
(C) \(\frac{5}{11}\)
Step-by-step Solution
Detailed explanation
Required probability= \( \frac{5}{6} \times \frac{1}{6}+\left(\frac{5}{6}\right)^3 \times \frac{1}{6}+\left(\frac{5}{6}\right)^5 \times \frac{1}{6}+\ldots \ldots \) \( =\frac{1}{6} \times \frac{\frac{5}{6}}{1-\frac{25}{36}}=\frac{5}{11}\)
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