JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
A common tangent \(T\) to the curves \(C_{1}: \frac{x^{2}}{4}+\frac{y^{2}}{9}=1\) and \(C_{2}: \frac{x^{2}}{42}-\frac{y^{2}}{143}=1\) does not pass through the fourth quadrant. If \(T\) touches \(C _{1}\) at ( \(\left.x _{1}, y _{1}\right)\) and \(C _{2}\) at \(\left( x _{2}, y _{2}\right)\), then \(\left|2 x _{1}+ x _{2}\right|\) is equal to \(......\)
- A \(19\)
- B \(18\)
- C \(17\)
- D \(20\)
Answer & Solution
Correct Answer
(D) \(20\)
Step-by-step Solution
Detailed explanation
\(T_{1}: y=m x \pm \sqrt{4 m^{2}+9}\) And \(T_{2}: y=m x \pm \sqrt{42 m^{2}-13}\) So, \(4\,m^{2}+9=42 m^{2}-143\) \(38\,m ^{2}=152\) \(m=\pm 2\) \(c=\pm 5\) For given tangent not pass through \(4^{\text {th }}\) quadrant \(T: y=2 x+5\) Now, comparing with…
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