JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
A circle passes through the points \((2, 3)\) and \((4, 5)\). If its centre lies on the line, \(y- 4x + 3 = 0\) , then its radius is equal to
- A \(\sqrt 5 \)
- B \(1\)
- C \(\sqrt 2 \)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(\sqrt 2 \)
Step-by-step Solution
Detailed explanation
Equation of the line passing through the point \((2,3)\) and \((4,5)\) \(y - 3 = \left( {\frac{{5 - 3}}{{4 - 2}}} \right)x - 2 \Rightarrow x - y + 1 = 0\,\,\,\,\,\,.......\left( 1 \right)\) Equation of the perpendicular line passing through the midpoint…
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