JEE Mains · Maths · STD 12 - 7.2 definite integral
\(\int \limits_{\pi / 6}^{\pi / 3} \tan ^{3} x \cdot \sin ^{2} 3 x\left(2 \sec ^{2} x \cdot \sin ^{2} 3 x+3 \tan x \cdot \sin 6 x\right) d x\) is equal to
- A \(\frac{9}{2}\)
- B \(-\frac{1}{9}\)
- C \(-\frac{1}{18}\)
- D \(\frac{7}{18}\)
Answer & Solution
Correct Answer
(C) \(-\frac{1}{18}\)
Step-by-step Solution
Detailed explanation
\(I =\int_{\pi / 6}^{\pi / 3}(\left(2 \tan ^{3} x \cdot \sec ^{2} x \cdot \sin ^{4} 3 x \right)\) \(+\left(3 \tan ^{4} x \cdot \sin ^{3} 3 x \cdot \cos 3 x \right)) dx\)…
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