JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\lambda \in R , \vec{a}=\lambda \hat{i}+2 \hat{j}-3 \hat{k}, \vec{b}=\hat{i}-\lambda \hat{j}+2 \hat{k}\) If \(((\vec{a}+\vec{b}) \times(\vec{a} \times \vec{b})) \times(\vec{a}-\vec{b})=8 \hat{i}-40 \hat{j}-24 \hat{k}\), then \(|\lambda(\vec{a}+\vec{b}) \times(\vec{a}-\vec{b})|^2\) is equal to
- A \(140\)
- B \(132\)
- C \(144\)
- D \(136\)
Answer & Solution
Correct Answer
(A) \(140\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ a }=\lambda \hat{ i }+2 \hat{ j }-3 \hat{ k }\) \(\overrightarrow{ b }=\hat{ i }-\lambda \hat{ j }+2 \hat{ k }\)…
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