ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 9. differential equations

If the solution curve of the differential equation \(\left(y-2 \log _e x\right) d x+\left(x \log _e x^2\right) d y=0, x > 1\) passes through the points \(\left(e, \frac{4}{3}\right)\) and \(\left(e^4, \alpha\right)\), then \(\alpha\) is equal to \(................\).

  1. A \(2\)
  2. B \(3\)
  3. C \(1\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3\)

Step-by-step Solution

Detailed explanation

\((y-2 \ln x) d x+(2 x \ln x) d y=0\) \(d y(2 x \ln x)=[(2 \ln x)-y] d x\) \(\frac{d y}{d x}=\frac{1}{x}-\frac{y}{2 x \ln x}\) \(\frac{d y}{d x}+\frac{y}{2 x \ln x}=\frac{1}{x}\) \(\text { I.F }=e^{\int \frac{1}{2 x \ln x} d x}\)…
Same subject
Explore more questions on app