JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The volume (in \(mL\) ) of \(0.1\, N\) \(NaOH\) required to neutralise \(10\, mL\) of \(0.1\, N\) phosphinic acid is........
- A \(15\)
- B \(18\)
- C \(10\)
- D \(5\)
Answer & Solution
Correct Answer
(C) \(10\)
Step-by-step Solution
Detailed explanation
\(H _{3} PO _{2}+ NaOH \rightarrow NaH _{2} PO _{2}+ H _{2} O\) \(\frac{ n _{ H_3 PO _{2}} \text { reacted }}{1}=\frac{ n _{ NaOH } \text { reacted }}{1}\) \(\Rightarrow \frac{0.1 \times 10}{1}=0.1 \times V _{ NaOH }\) \(\Rightarrow V _{ NaOH }=10 ml\)
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