JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
The reaction in which the hybridisation of the underlined atom is affected is
- A \(\underline{N}{H }_{3} \stackrel{ H ^{+}}{\longrightarrow}\)
- B \(\underline {Xe}F _{4}+ SbF _{5} \rightarrow\)
- C \(H _{2} \underline SO _{4}+ NaCl \xrightarrow{{420\,\,K}}\)
- D \(H _{3} \underline PO _{2} \xrightarrow{{ Disproportionation }}\)
Answer & Solution
Correct Answer
(B) \(\underline {Xe}F _{4}+ SbF _{5} \rightarrow\)
Step-by-step Solution
Detailed explanation
\(XeF _{4}+ SbF _{5} \rightarrow\left[ XeF _{3}\right]^{+}\left[ SbF _{6}\right]^{-}\) \(sp ^{3} d ^{2}\,\,\,\,\, sp ^{3} d\,\,\, \quad sp ^{3} d\,\,\,\,\, \quad sp ^{3} d ^{2}\)
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